Out of the box
Ones upon a time one old man was living with three sons. Old man had 19 Cows. One day he fell ill and after his death , his son read the will.
1) My eldest son will get 1/2 of my cows
2) My second son will get 1/4 of my cows
3) my youngest son will get 1/5 of my cows
Can you distribute the cows as per will. How many cows each of them got ?
Question : For any 9 digit number not ending in Zero. Prove that sum of this number with the number formed by writing its digits in reverse order will always contain at least one even digit ?
Hint : middle digit of sum (S5) is twice of the middle digit of said number so S5 will be even . Now to make the S5 to odd we need carry from the S4. In this case S6 will also generate the carry if S3 is odd the carry of S6 will make the S7 to even number.
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Question :
1) My eldest son will get 1/2 of my cows
2) My second son will get 1/4 of my cows
3) my youngest son will get 1/5 of my cows
Can you distribute the cows as per will. How many cows each of them got ?
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Hint : middle digit of sum (S5) is twice of the middle digit of said number so S5 will be even . Now to make the S5 to odd we need carry from the S4. In this case S6 will also generate the carry if S3 is odd the carry of S6 will make the S7 to even number.
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Question :
Answer 1000 /-
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Question :
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Question : Is it possible to put the numbers from 1 to 64 in the squares of a chess board in such a way that the sum of the numbers in any three squares arranged in the following pattern will be odd?
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